![]() It is also used for describing, visualizing, and documenting different facets of a system.Ĭlass diagrams are the only UML diagrams that can be mapped directly with object-oriented languages. This helps software engineers in developing the code for an application. A class diagram shows the classes, attributes, operations, and the relationship between them. Notice that your question should be worded: "What kind of association is it?" instead of "What kind of composition is it?" because composition and aggregation are special types of associations.A class diagram is a static structure that is used in software engineering. It may be a composition, if you have the additional semantics of an aggregate-component relationship. In any case, the relationship between the classes A and B is an association. this symbol has a different meaning in UML (the multiplicity unbounded).there is no need to use such a symbol in UML because it's clear that the attribute references B objects.it is Cpp-specific, while your diagram should probably be platform-independent.You cannot use the C++ symbol "*" in the UML class diagram because For more explanation see Chapter 5 of this tutorial. It means that the association end with name "attribute" is owned by class A, which means that it corresponds to the reference property shown in the diagram above (the association can be replaced with the reference property). Notice the "dot" at the B side of the association line. Such a reference property expresses a uni-directional (binary) association, as shown in the following diagram: That means there is a relationship is called association.Ī plain C++ pointer directly corresponds to a reference property in a UML class diagram, as shown in the following diagram: If your class uses another class but does not keep instances (or references/pointers) to that class, then you can denote dependency by just a simple line (solid) between the objects. Where when you see an empty diamond you may use reference, or pointer. Now, traditionally when you see a filled diamond, you usually (not all the time) will have an object by value. left the company) then the TeamLeadRole is still available. An employer has a TeamLeadRole, but when the employer is "destroyed" (i.e. For example you will not expect to see that the owned object being deleted in the destructor. When the diamond is not filled (aggregation), then the owner is not responsible to manage the life of the object owned. The hands do not survive when the human object is destroyed. So the owner has to manage the life time of the owned object. So, for a referenced object (has relationship) that dies when the owner is destroyed, you have to use a solid (filled) diamond. What is really important is to say what is the lifetime of the referenced object. ![]() That is because there is no destructor that deletes what A.attribute pointer references. Quick answer: from your code, A aggregates B (empty diamond at A class, connecting B with a solid line). Why? Because, you may be using UML describing an OOD for a language without pointers. In UML it is not as important to show whether it is a pointer or not.
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